4y^2-48=y^2

Solution for 4y^2-48=y^2 equation:

Simplifying
4y2 + -48 = y2

Reorder the terms:
-48 + 4y2 = y2

Solving
-48 + 4y2 = y2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y2' to each side of the equation.
-48 + 4y2 + -1y2 = y2 + -1y2

Combine like terms: 4y2 + -1y2 = 3y2
-48 + 3y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-48 + 3y2 = 0

Add '48' to each side of the equation.
-48 + 48 + 3y2 = 0 + 48

Combine like terms: -48 + 48 = 0
0 + 3y2 = 0 + 48
3y2 = 0 + 48

Combine like terms: 0 + 48 = 48
3y2 = 48

Divide each side by '3'.
y2 = 16

Simplifying
y2 = 16

Take the square root of each side:
y = {-4, 4}